How do you write the equation of a line that is perpendicular to the given line and that passes through the given point: y-4=5/2(x+3); (-7,8)?

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Answer 1 · 2018-06-13T10:36:28

#y=-2/5x+26/5#

#y-4=5/2 (x+3)#

#2y-8=5x+15#

#2y=5x+23#

#y=5/2x+23/2#

if it is perpendicular then when you multiply the gradients together you get -1

so the gradient of the new line is #-2/5#

The line is of the form #y=-2/5x+c# but we know it passes through (-7,8) so if we put these values in we will get the equation.

#8=-2/5xx-7+c#

#8=14/5+c#

#c=5 1/5#