Question

How do you solve `e^ { x ^ { 2} + 14x } = \frac { 1} { e ^ { 48} }`?

Answer 1

`x_1=-8` and `x_2=-6`

Explanation:

`color(white)(xx)e^(x^2+14x)=e^-48`
`=>x^2+14x=-48`
`=>x^2+14x+48=0`
`=>(x+8)(x-6)=0`
`=>x_1=-8` and `x_2=-6`