Question

Differentiate; 3ln(x^2+1) ? Thanking the person(s) to help me in advance :)

Answer 1

`(6x)/(x^2+1)`

Explanation:

You need to know two major things for this:
1. Chain rule
2. The derivative of `ln(x)` is `1/x`
when you take the derivative you will get
`3*1/(x^2+1)*` the derivative of `x^2+1` (because of chain rule)
so it's `3*1/(x^2+1)*2x`
= `(6x)/(x^2+1)`

Answer 2

`(6x)/(x^2+1)`

Explanation:

`"differentiate using the "color(blue)"chain rule"`

`"given "y=f(g(x))" then"`

`dy/dx=f'(g(x))xxg'(x)larrcolor(blue)"chain rule"`

`d/dx(3ln(x^2+1))`

`=3xx1/(x^2+1)xxd/dx(x^2+1)`

`=3/(x^2+1)xx2x=(6x)/(x^2+1)`