Question

Integrate 4sin 2t dt?

Answer 1

I tried this:

Explanation:

Considering:

`int4sin(2t)dt=`

set `2t=p`
so: `2dt=dp`
and: `dt=(dp)/2`

substitute:

`int4sin(2t)dt=intcancel(4)^2sin(p)(dp)/cancel(2)=2intsin(p)dp=-2cos(p)+c`

but: `p=2t` so going back to our original variable we get:

`int4sin(2t)dt=-2cos(2t)+c`