Question

How do you solve `x^ { 2} + 75x + 56= 0`?

Answer 1

use the quadratic formula

`x=[-b\pmsqrt{b^2-4ac}]/(2a)`

where `a=1, b=75 and c=56`

`x=[-75\pmsqrt[5401]]/2`

`x=[-75+sqrt5401]/2 or x=[-75-sqrt5401]/2`

`x=-0.7542519467 or x= -74.24574805`