How do you solve #9e^(1.4p-10)-10=17#?

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Answer 1 · 2018-06-14T12:36:20

#p = \frac{ln(3)+10}{1.4}#

Add #10# to both sides:

#9e^{1.4p-10}=27#

divide both sides by #9#:

#e^{1.4p-10}=3#

consider the natural logarithm of both sides, leveraging the fact that #ln(e^x) = x#

#1.4p-10 = ln(3)#

Add #10# to both sides:

#1.4p = ln(3)+10#

Divide both sides by #1.4#:

#p = \frac{ln(3)+10}{1.4}#