How do you decide whether the relation #7x^2+y^2=1# defines a function?

1 Answer
Jun 14, 2018

It doesn't because one input value yields more than one output value.

Explanation:

A function is simply a rule that states how the inputs and outputs must be related.

For example, #f(x) = y = sin(x)# means that the rule is that, for any input #x#, the output will be the sine of that input.

In your case, if we solve the expression for #y# in order to highlight this "rule", we have

#y^2 = 1-7x^2 \iff y = \pm sqrt(1-7x^2)#

That #pm# sign means that, given a certain input #x#, the output can be either #sqrt(1-7x^2)# or #-sqrt(1-7x^2)#.

Since it is not true that every input yields one and only one output, this is not a function.