Find the exact value of the trigonometric expression given that sin(u) = − 3/5, where 3π/2 < u < 2π, and cos(v) = 15/17, where 0 < v < π/2. ? cos(u−v)

Find the exact value of the trigonometric expression given that
sin(u) = − 3/5, where 3π/2 < u < 2π, and cos(v) = 15/17,
where 0 < v < π/2. ?

cos(u−v)

1 Answer
Jun 15, 2018

cos (u - v) = 36/85cos(uv)=3685

Explanation:

Trig identity:
cos (u - v) = cos u.cos v + sin u.sin v (1)
sin u = - 3/5sinu=35. Find cos u
cos^2 u = 1 - sin^2 u = 1 - 9/25 = 16/25cos2u=1sin2u=1925=1625
cos u = 4/5cosu=45 (because u lies in Quadrant 4)
cos v = 15/17cosv=1517. Find sin v.
sin^2 v = 1 - cos^2 v = 1 - 225/289 = 64/289sin2v=1cos2v=1225289=64289
sin v = 8/17sinv=817 (because v lies in Quadrant 1)
Replace these above values into identity (1)
cos (u - v) = (15/17)(4/5) + (-3/5)(8/17) = 36/85cos(uv)=(1517)(45)+(35)(817)=3685