Question

How do you solve `20^(n-2)+6.5=87`?

Answer 1

`n=(ln(80.5)+2ln(20))/ln(20)`

Explanation:

First, we subtract 6.5 from both sides to get
`20^(n-2)=80.5`
Taking the natural log (or whatever base you choose), we get
`(n-2)ln(20)=ln(80.5)`
`nln(20)-2ln(20)=ln(80.5)`
`nln(20)=ln(80.5)+2ln(20)`
`n=(ln(80.5)+2ln(20))/ln(20)`