#"H"_3"C"-"C"="CH" + "HBr" -> #?
1 Answer
Jun 16, 2018
This may be what you mean:
-
The
#"H"^(+)# from#"HBr"# , a strong acid, simply protonates a carbon on the#pi# bond by responding to the#pi# electrons coming in towards the#"H"# on#"HBr"# .This alkene follows Markovnikov addition, meaning that the
#"H"^(+)# goes onto the carbon with more hydrogens than the other one. Carbons 1 and 2 were choices, and we would then choose carbon 1. -
Hence, carbon 2 becomes the carbocation when the secondary carbocation intermediate forms. At that point,
#"Br"^(-)# acts as a nucleophile to add onto carbon 2 to yield#color(blue)"2-bromopropane"# .