What is the center and radius of the circle with equation (x+8)^2+(y+3)^2=6.25?
what is the center and radius of the circle with equation (x+8)^2+(y+3)^2=6.25
what is the center and radius of the circle with equation (x+8)^2+(y+3)^2=6.25
1 Answer
Jun 18, 2018
Refer to the explanation.
Explanation:
The equation of a circle is given by:
where:
#(h,k)# are the coordinates of the circle's center
#r# is the radius of the circle
Here, we see that
The radius is therefore:
graph{(x-8)^2+(y+3)^2=6.25 [-4.5, 15.5, -7.6, 2.4]}