How do you solve $\frac { 1} { 4} p - \frac { 3} { 10} = \frac { 5} { 6} p - 3$ ?

Question

1069 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-19T22:10:13

$p=162/35$

$p/4-3/10=(5p)/6-3$

$(5p)/6-p/4=3-3/10$

$(7p)/12=27/10$

$p=27/10*12/7=162/35$

How do you solve \frac { 1} { 4} p - \frac { 3} { 10} = \frac { 5} { 6} p - 3\frac { 1} { 4} p - \frac { 3} { 10} = \frac { 5} { 6} p - 3?