Question

If a current of `6 A` passing through a circuit generates `12 W` of power, what is the resistance of the circuit?

Answer 1

`1/3\ \Omega`

Explanation:

Power (`P`) of a circuit carrying a current `I` & having a resistance `R` is given as
`P=I^2R`
but given that `I=6A` & power `P=12 W` hence
`12=6^2R`
`R=\frac{12}{36}`
`R=1/3\ \Omega`

Answer 2

Approximately `0.33` ohms.

Explanation:

Power is related through resistance and current by the equation:

`P=I^2R`

where:

• `P` is the power in watts

• `I` is the current in amperes

• `R` is the resistance in ohms

Rearranging for resistance, we get:

`R=P/I^2`

Now, plugging in our given values, we find that:

`R=(12 \ "W")/(6 \ "A")^2`

`=(12 \ "W")/(36 \ "A"^2)`

`=1/3 \ Omega`

`~~0.33 \ Omega`