How do you solve 3= 7 (4-2u)-6u3=7(4−2u)−6u?

2 Answers
Jim G.
Jun 20, 2018

u=5/4u=54

Explanation:

"distribute and simplify right side of equation"distribute and simplify right side of equation

3=28-14u-6u3=28−14u−6u

3=28-20u3=28−20u

"subtract 28 from both sides"subtract 28 from both sides

3-28=-20u3−28=−20u

-25=-20u−25=−20u

"divide both sides by "-20divide both sides by −20

(-25)/(-20)=urArru=5/4−25−20=u⇒u=54

color(blue)"As a check"As a check

Substitute this value into the right side of the equation and if equal to the left side then it is the solution.

7(4-5/2)-15/2=21/2-15/2=6/2=37(4−52)−152=212−152=62=3

u=5/4" is the solution"u=54 is the solution

Bhavin B.
Jun 20, 2018

u=5/4=1.25u=54=1.25

Explanation:

Open the brackets and simplify further:

3=7(4-2u)-6u3=7(4−2u)−6u

3=(7 xx 4) - (7 xx 2u) - 6u3=(7×4)−(7×2u)−6u

3=28-14u-6u3=28−14u−6u

3=28-20u3=28−20u

Subtract 2828 both sides:

3-28=28-28-20u3−28=28−28−20u

-25=cancel(28-28)-20u

-25=-20u

Multiply by -1 both sides to get rid of negative sign:

-25 xx (-1) = -20u xx (-1)

25=20u

Divide by 20 both sides:

25/20 = (20u)/20

5/4=u

Check the answer:

3=7(4-2u)-6u

3=7(4-2(1.25))-6(1.25)

3=7(4-5/2)-15/2

3=7(4-2.5)-7.5

3=10.5-7.5
3=3---> Correct!

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