Question

What is the derivative of y=sin(tan2x) ?

Answer 1

See below

Explanation:

`y' = cos(tan 2x) * D_u ((sin u)/(cos u)) * D_x u` where `u = 2x`

`y' = cos(tan 2x) * (cos^2 u+ sin^2 u)/(cos^2 u) * 2`

`y' = cos(tan 2x) * (2)/(cos^2 2x)`