Question

Integrate the following function `int_0^1(e^z+1)/(e^z+z)dz` ?

Answer 1

`int_0^1(e^z+1)/(e^z+z)dz=ln(e+1)`

Explanation:

`int_0^1(e^z+1)/(e^z+z)dz=int_0^1((e^z+z)')/(e^z+z)dz=int_0^1(ln(e^z+z))'dz=[ln(e^z+z)]_0^1=ln(e+1)-ln1=ln(e+1)`