How do you solve #28= - 6y - 12+ 2y#?

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Answer 1 · 2018-06-21T14:42:17

#y=-10#

#28= - 6y - 12+ 2y#

combine like terms:

#28= - 4y - 12#

add #12# to both sides:

#40=-4y#

divide both sides by #-4#

#-10=y#