How do you calculate $(3.2 times 10^-2)( 5 times 10^-3)$ ?

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Answer 1 · 2018-06-22T08:54:58

multiply the numbers together

$3.2 xx 5= 16$

Now deal with the powers of 10

$10^-2 xx 10^-3 = 10^(-2 + -3) = 10^-5$

Putting these two together

$(3.2xx10^-2)(5xx10^-3)=16xx10^-5$

Putting the answer into scientific form

$1.6xx10^-4$

Or as a normal number

0.00016

How do you calculate (3.2 times 10^-2)( 5 times 10^-3)(3.2 times 10^-2)( 5 times 10^-3)?