How do you solve #(y-1)/(y) = 10#?

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Answer 1 · 2018-06-22T18:56:12

#y = -1/9#

#(y-1)/y = 10#

We want to isolate #y# (get #y# by itself), so use this series of steps:

First, multiply both sides by #color(blue)y#:
#(y-1)/y color(blue)(*y) = 10 color(blue)(*y)#

#y-1 = 10y#

Now subtract #color(blue)y# from both sides:
#y - 1 quadcolor(blue)(-quady) = 10y quadcolor(blue)(-y)#

#-1 = 9y#

Finally, divide both sides by #color(blue)9#:
#(-1)/color(blue)9 = (9y)/color(blue)9#

Therefore,
#y = -1/9#

Hope this helps!