How do I find the value of #log 100#?

1 Answer

#log100=2#

Explanation:

One way we can approach log problems is to remember that

#a^b=c <=> log_ac=b#

In our question, since the value of #a# in the right hand side log isn't specifically listed, it's assumed to be 10. So what we have is:

#a^b=c <=> log_10(100)=b#

#10^b=100 <=> log_10(100)=b#

By observation of the left hand side, we can see that #b=2#