A projectile is shot from the ground at an angle of #(5 pi)/12 # and a speed of #2 m/s#. Factoring in both horizontal and vertical movement, what will the projectile's distance from the starting point be when it reaches its maximum height?
1 Answer
The distance is
Explanation:
The initial speed is
The angle is
The equation of the trajectory of the projectile is
At the maximum height
Therefore,
and
Plugging this value of
The acceleration due to gravity is
Therefore,
The distance from the starting point to the greatest height is