How do you solve #lnsqrt(x) = 3#?

1 Answer
Patrick H.
Jun 23, 2018

Rearrange the expression so its shown as an exponential function.

Explanation:

You probably know that #ln#, or "natural logarithm" for short, has #e# as its base. You may also know that a logarithm #log_a b=x# can be rewritten as #a^x=b#. Let's rewrite the expression using these:

#log_e sqrt(x)=3#
#e^3=sqrt(x)#

Next, let's square each side to get our answer:

#(e^3)^2=(sqrt(x))^2#
#e^6=x~~403.43#

Related questions
Impact of this question
1063 views around the world
You can reuse this answer
Creative Commons License