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Answer 1 · 2018-06-24T00:03:38

#=(x(x-1))/2#

.

#(x^2(x^2-2x+1)lne^xsin(pi/4))/((x^(-1))^(-1)e^lnx(x-1)sqrt2)#

#lne^x=xlne=x#

#sin(pi/4)=sqrt2/2#

#(x^(-1))^(-1)=x^((-1)(-1))=x^(+1)=x#

#e^lnx=x#

#(x^2-2x+1)=(x-1)^2#

Let's substitute all of them:

#(x^2(x^2-2x+1)lne^xsin(pi/4))/((x^(-1))^(-1)e^lnx(x-1)sqrt2)=#

#(x^2(x-1)^2xsqrt2/2)/(x*x(x-1)sqrt2)=(x-1)x(1/2)=(x(x-1))/2#