How do you solve the following system?: #7x -3y =11, -9x -24y = -7#

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Answer 1 · 2018-06-24T15:22:52

#x=19/13# and #y=-10/39#

#8*(7x-3y)-(-9x-24y)=8*11-(-7)#

#56x-24y+9x+24y=88+7#

#65x=95#, so #x=95/65=19/13#

Thus,

#7*19/13-3y=11#

#133/13-3y=11#

#-3y=10/13# or #y=-10/39#

Answer 2 · 2018-06-24T15:24:58

#x=19/13,y=-10/39#

Multiplying the first equation by #-8# and adding to the second we get

#-65x=-95#
so
#x=95/65=19/13#
plugging this in the first equation we get

#7*19/13-3y=11#
#133/13-11=3y#

#(133-143)/13=3y#

#-10/13=3y#

so

#y=-10/39#