@Ultrilliam wrote an answer with the help of
Binomial Expansion. This method is short.
I have tried to solve with the help of formula given below.
This method need some adjustment for #A#
#(1)lim_(xtoa) (x^n-a^n)/(x-a)=n*a^(n-1) orcolor(red)( lim_(XtoA) (X^n-A^n)/(X-A)=n*A^(n-1)#
........................................................................................................
Let,
#L=lim_(xto7)(root(3)(1+x)-root(3)(2x-6))/(sqrt(7x)-sqrt(7+6x))#
#=lim_(xto7)(root(3)(1+x)-root(3)(2x-6))/(sqrt(7x)-
sqrt(7+6x))xxcolor(blue)
((sqrt(7x)+sqrt(7+6x))/(sqrt(7x)+sqrt(7+6x))#
#=lim_(xto7)(root(3)(1+x)-root(3)(2x-6))/((7x)-
(7+6x))xxcolor(blue)((sqrt(7x)+sqrt(7+6x))#
#=lim_(xto7)((1+x)^(1/3)-color(violet)((8)^(1/3))-(2x-6)^(1/3)+color(violet)((8)^(1/3)))/(x-
7)xx{sqrt(49)+sqrt(49)}#
#=14{lim_(xto7)((1+x)^(1/3)-(8)^(1/3))/(x-7)-lim_(xto7)((2x-
6)^(1/3)-(8)^(1/3))/(x-7)}#
#=14{color(red)(lim_(xto7)((1+x)^(1/3)-(8)^(1/3))/((1+x)-(8))-lim_(xto7)((2x-
6)^(1/3)-(8)^(1/3))/((2x-6)-(8)))xx2}#
#=14{color(red)(1/3*(8)^(1/3-1)-1/3*(8)^(1/3-1))xx2}...tocolor(red)(Apply(1)#
#=14/3{(2^3)^(-2/3)-(2^3)^(-2/3)xx2}#
#=14/3{2^(-2)-2*2^(-2)}#
#=14/3{1/4-2/4}#
#=14/3*(-1/4)#
#=-7/6#