Question

A sound has speed of 330m/s and frequency of 50Hz what is the possible distance between 2 points on wave that have phase difference of 60°?

Answer 1

Any 2 points on wave that have phase difference of 60° are separated by a distance of 1.1 m.

Explanation:

The wavelength of this wave is

`lambda = v/f = (330 m/cancel(s))/(50/cancel(s)) = 6.6 m`

Since `60^@ " is " 1/6 th` of the total wavelength,

The possible distance between 2 points on wave that have phase difference of `60° = 6.6 m * 1/6 = 1.1 m`

I hope this helps,
Steve