Question

How to find dy/dx implicit differentiation? sin(x+y) + sin (x-y) = 1

Answer 1

`cotxcoty=dy/dx`

Explanation:

1. `sin(a+b)+sin(a-b)=2sin(a)cos(b)`

Therefore our question simplifies to `2sinxcosy=1`

1. Implicit Differentiation using product rule

`2(cosxcosy-sinxsinydy/dx)=0`

`cosxcosy=sinxsinydy/dx`

`(cosxcosy)/(sinxsiny)=dy/dx`

`cotxcoty=dy/dx`