If 2,5 and x,6 are the endpoints of a segment with length √17,what is the value of x ?

1 Answer
Jun 26, 2018

#x=6# or #x=-2#

Explanation:

By the Pythagorean Theorem
#color(white)("XXX")sqrt((x-2)^2+(6-5)^2)=sqrt(17)#

#color(white)("XXX")(x-2)^2+1=17#

#color(white)("XXX")x^2-4x+4+1-17=0#

#color(white)("XXX")x^2-4x-12=0#

#color(white)("XXX")(x-6)(x+2)=0#

So #x=6# or #x=-2#