How do you draw the graph of #y=2x-1#?

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Answer 1 · 2018-06-26T16:18:49

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For #x = 0#

#y = (2 * 0) - 1#

#y = 0 - 1#

#y = -1# or #(0, -1)#

Second Point: For #y = 2#

#y = (2 * 2) - 1#

#y = 4 - 1#

#y = 3# or #(2, 3)#

We can next plot the two points on the coordinate plane:

graph{(x^2+(y+1)^2-0.035)((x-2)^2+(y-3)^2-0.035)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y - 2x + 1)(x^2+(y+1)^2-0.035)((x-2)^2+(y-3)^2-0.035)=0 [-10, 10, -5, 5]}