Integrate the following function #int_0^1(e^z+1)/(e^z+z# #dz#? Need help with u substitution?
I have already asked this question (socratic link) but I'm not sure how to use u- substitution to get #[ln(e^z+z)]_0^1# . Would I start off by letting #u=e^z+z# ? And then #du=(e^z+1)dx# ? Which steps would I need to do next?
I have already asked this question (socratic link) but I'm not sure how to use u- substitution to get
1 Answer
Jun 27, 2018
Please see below.
Explanation:
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