Question

Can someone please help me figure out F(u) ?

Answer 1

`f(u)=1/6u^3`

Explanation:

`int_1^5((6x-2)^3)dx`

Let `u=6x-2` then `(du)/6=dx`

Find new bounds

`u=6(1)-2=4, u=6(5)-2=28`

`int_1^5((6x-2)^3)dx = int_4^28(1/6u^3)du`

`f(u)=1/6u^3`