Radio signals travel at a rate of $3 \times 10^{8}$ $3 × 10^8$ meters per second. How many seconds will it take for a radio signal to travel from a satellite to the surface of the Earth if the satellite is orbiting at a height of $7.5 \times 10^{6}$ $7.5 × 10^6$ meters?

Question

12076 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-27T15:35:32

${7.5 times 10^6\ "meters" }/{3 times 10^8\ "meters/sec"} =7.5/3 times 10^{-2} \ "sec" = 2.5 times 10^{-2}\ "sec" = .025\ "sec"$

Radio signals travel at a rate of 3 × 10^83×1083 × 10^8 meters per second. How many seconds will it take for a radio signal to travel from a satellite to the surface of the Earth if the satellite is orbiting at a height of 7.5 × 10^67.5×1067.5 × 10^6 meters?