How do you solve the following system: # 3x + y = 2 , 4x + y = 2 #?

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Answer 1 · 2018-06-27T22:11:25

See a solution process below:

First, subtract the two equations:

#color(white)(-)4x + y = 2#
#-(3x + y = 2)#
#"---------------------"#

#color(white)(-)4x + y = 2#
#-3x - y = -2#
#"-----------------------"#
#1x + 0y = 0#

#1x = 0#

#x = 0#

Now, substitute #0# for #x# in either equation and calculate #y#:

#3x + y = 2# becomes:

#(3 xx 0) + y = 2#

#0 + y 2#

#y = 2#

The Solution Is:

#x = 0# and #y = 2#

Or

#(0, 2)#