Question

A baseball is a square that is90 feet on each side.what is the distance a catcher had to to throw the ball from home to second base?

Answer 1

See a solution process below:

Explanation:

Because the baseball field is a square, the angles at the corner are right angles.

Therefore, the throw from home plate to second base makes a hypotenuse for a right triangle.

Therefore, we can use the Pythagorean Theorem to find the distance between home plate and second base.

The Pythagorean Theorem states:

`c = sqrt(a^2 + b^2)` Where:

`c` is the length of the hypotenuse of the right triangle

`a` and `b` are the length of the sides of the right triangle

Substituting `90" ft"` for `a` and `b` and calculate `c` gives:

`c = sqrt((90" ft")^2 + (90" ft")^2)`

`c = sqrt(8100" ft"^2 + 8100" ft"^2)`

`c = sqrt(8100" ft"^2 xx 2)`

`c = sqrt(8100" ft"^2)sqrt(2)`

`c = 90sqrt(2)" ft"`

`c ~= 127" ft"`