Two electrons are 1m apart , show that the force beyween them is 2.304 x 10^(-3) ?

1 Answer

2.304\times10^{-28}\ N

Explanation:

Force of repulsion (F) between two electrons (each having charge e=1.6\times10^{-19}\ C) separated by a distance r=1\ m is given as

F=\frac{1}{4\pi \epsilon_o}\frac{q_1q_2}{r^2}

F=9\times10^{9}\cdot \frac{1.6\times10^{-19}\cdot 1.6\times10^{-19}}{1^2}

=23.04\times 10^{-29}

=2.304\times10^{-28}\ N