How do you simplify #\frac{(3(-2-1)^{2}+4)(3-2\times (-2))}{3^{-1}(3^{2}+3)}#?

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Answer 1 · 2018-06-28T23:14:29

#-31/4#

Applying PEDMAS

#\frac{(3(-2-1)^2+4)(3-2\times(-2))}{3^{-1}(3^2+3)}#

#=\frac{(3\times 9+4)(3-4)}{3^{-1}(9+3)}#

#=\frac{(27+4)(-1)}{3^{-1}(9+3)}#

#=\frac{(31)(-1)}{3^{-1}(12)}#

#=-\frac{31}{1/3(12)}#

#=-\frac{31}{4}#