Question

The question is below?

Find the sum of the series `1+1/(4*2!)+1/(16*4!)+1/(64*6!)...oo`

Answer 1

See below.

Explanation:

Sorry, at first I could not see the formula of this series. But now I see that it is made up the following way

`S_n=1/(4^n*(2n)!)` for `n=0, 1, 2, ...oo`
and the sum is then
`S = Sigma_(n=0)^oo S_n`

As I don't see the answer offhand, I wanted to delete my answer, which I am not allowed to. But perhaps someone can continue from there. (Or I'll come back if I work it out.)