How many atoms of each element of AgNO_3AgNO3 are in 0.15 mol of AgNO_3AgNO3?

1 Answer
Dr. K.
Jun 29, 2018

9.0"x"10^22"Ag atoms"9.0x1022Ag atoms

9.0"x"10^22"N atoms"9.0x1022N atoms

2.7"x"10^23"O atoms"2.7x1023O atoms

Explanation:

  1. From 0.15mol of AgNO_3AgNO3, we can find the moles of each element by counting how many of each element is present in the entire compound. In AgNO_3AgNO3, there's 1 Ag, 1 N and 3 O.
  2. Then, we convert from moles of each element to the number of atoms using Avogadro's number 6.02"x"10^236.02x1023.

I went ahead and set up the two steps above in 1 line for each element:
"Ag atoms"=0.15 "mol " AgNO_3*(1 "mol " Ag)/(1 "mol " AgNO_3)*(6.02"x"10^23 "Ag atoms")/(1 "mol " Ag)=9.0"x"10^22"Ag atoms"Ag atoms=0.15mol AgNO3⋅1mol Ag1mol AgNO3⋅6.02x1023Ag atoms1mol Ag=9.0x1022Ag atoms

"N atoms"=0.15 "mol " AgNO_3*(1 "mol " N)/(1 "mol " AgNO_3)*(6.02"x"10^23 "N atoms")/(1 "mol " N)=9.0"x"10^22"N atoms"N atoms=0.15mol AgNO3⋅1mol N1mol AgNO3⋅6.02x1023N atoms1mol N=9.0x1022N atoms

"O atoms"=0.15 "mol " AgNO_3*(3 "mol " O)/(1 "mol " AgNO_3)*(6.02"x"10^23 "O atoms")/(1 "mol " O)=2.7"x"10^23"O atoms"O atoms=0.15mol AgNO3⋅3mol O1mol AgNO3⋅6.02x1023O atoms1mol O=2.7x1023O atoms

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