Question

Solve for x : (3x^2+x+1)-(10(3x^2+x-1)÷ 3x^2+x=7?

Answer 1

`x=-10,0` or
`x\approx0.46179`,
`x\approx1.70085`,
`x\approx-2.82931`

Explanation:

This is a guess because I am not sure what you are asking.

Assuming you meant
"solve for `x`: `(3x^2+x+1)-(10(3x^2+x-1))/(3x^2)+x=7` ..." ?

Follow these steps:
1. `(3x^2+x+1)+x-7=(10(3x^2+x-1))/(3x^2)`
2. `3x^2+2x-6=(30x^2+10x-10)/(3x^2)`
3. `3x^2(3x^2+2x-6)=30x^2+10x-10`
4. `9x^4+6x^3-18x^2=30x^2+10x-10`
5. `9x^4+6x^3-18x^2-30x^2+10x=-10`
6. `9x^4+6x^3-48x^2+10x=-10`
7. `x(\color(red)(9x^3+6x^2-48x+10))=-10`

So `x=-10` OR you can solve that giant expression in red.
By the way, you can see the steps here. It's long, I'm warning you.