Why log_(2)^2x(5/(log_(2)3*log_(2)4)+1/log_(2)^(2)5)=0 equal to log_(2)^2x=0?

1 Answer
Jun 30, 2018

I tried this:

Explanation:

The entire bit inside the brackets is a number, say, n; it can go to the right of the = sign as:

log_2^2x=0/n=0

giving your conclusion in the question;

we can continue and rearrange to write:

sqrt(log_2^2x)=sqrt(0)

log_2x=0

using the definitio of log:

x=2^0=1