How do you differentiate $f(x)=(e^x+1)(x+1)sqrt(x^2-3)$ using the product rule?

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Answer 1 · 2018-06-30T22:15:05

$f'(x)=e^x * (x+1) * sqrt(x^2-3)+(e^x+1) * sqrt(x^2-3)+((e^x+1) * (x+1) * x)/sqrt(x^2-3)$

$f(x)=u*v*s$
$f'(x)=u'*v*s+u*v'*s+u*v*s'$

$f(x)=(e^x+1) * (x+1) * sqrt(x^2-3)$
$f'(x)=e^x * (x+1) * sqrt(x^2-3)+(e^x+1) * sqrt(x^2-3)+((e^x+1) * (x+1) * x)/sqrt(x^2-3)$

How do you differentiate f(x)=(e^x+1)*(x+1)*sqrt(x^2-3) f(x)=(e^x+1)*(x+1)*sqrt(x^2-3) using the product rule?