How do you solve #2t - 2 = 19 - t#?

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Answer 1 · 2018-07-02T06:37:50

#t=7#

Given: #2t-2=19-t#.

Add #t# to both sides.

#2t+t-2=19-color(red)cancelcolor(black)t+color(red)cancelcolor(black)t#

Add like-terms.

#3t-2=19#

Add #2# to both sides.

#3t-color(red)cancelcolor(black)2+color(red)cancelcolor(black)2=19+2#

#3t=21#

Divide by #3# to isolate #t#.

#(color(red)cancelcolor(black)3t)/(color(red)cancelcolor(black)3)=21/3#

#t=7#

Answer 2 · 2018-07-02T06:39:58

#t = 7#

Given: #2t - 2 = 19 - t#

Add #t# to both sides:

#t + 2t - 2 = 19 - t + t#

#3t - 2 = 19#

Add #2# to both sides:

#2 + 3t - 2 = 19 + 2#

#3t = 21#

Divide both sides by #3#:

#t = 21/3 = 7#