How do you solve #2( a - 3) = 4a - ( 2a - 6)#?

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Answer 1 · 2018-07-02T23:39:12

First, simplify
then solve, remembering PEMDAS(parentheses, exponents, multiply, divide, add, subtract) go in order

#2(a-3) = 4a-(2a-6)#

#2a-6=4a-2a+6#

then you combine like terms

#2a-6 =2a+6#

add six to both sides

#2a=2a+12#

since this is not mathematically possible, our equation has no solutions. A given quantity can't be equal to that given quantity plus #12#.

Hope this helps!

Answer 2 · 2018-07-03T03:51:29

No solutions

On the left, we can distribute the #2# and on the right we can distribute the negative sign. We now have

#2a-6=4a-2a+6#

Combining like terms on the right gives us

#2a-6=2a+6#

We cannot subtract six from a value and have it be equal to that value plus #6#, because #-6!=6#.

To further solve this equation, we get

#2a=2a+12#

#a=a+6#

#cancela=cancela+6#

#0!=6#

There are no #a# values that make this equation true.

Hope this helps!