How do you solve #(x+4)/3 = 2#?

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Answer 1 · 2018-07-03T04:04:44

#x = 2#

#(x + 4) / 3= 2#

#x + 4 = 2 * 3 = 6#

#x = 6 - 4 = 2#

Answer 2 · 2018-07-03T04:06:16

#x = 2#

Given: #(x +4)/3 = 2#

Solve means find the #x# value that works in the equation.

First multiply both sides by #3#:

#cancel(3)/1 * (x +4)/cancel(3) = 2 * 3#

#x + 4 = 6#

Subtract #4# from both sides to isolate the variable:

#x + 4 - 4 = 6 - 4#

#x = 2#