The population of Springfield is currently 41,250. If Springfield’s population increases by 2% of the previous year’s population, use this information to find the population after 4 years?

2 Answers
Jul 3, 2018

population after #4# years is #44,650# people

Explanation:

Given: Springfield, population #41,250# is increasing population by #2 %# per year. What is the population after #4# years?

Use the formula for increasing population: #P(t) = P_o (1 + r)^t#

where #P_o# is the initial or current population,

#r = #rate #= %/100# and #t# is in years.

#P(4) = 41,250 (1 + 0.02)^4 ~~ 44,650# people

Jul 3, 2018

Years in order: starting with a population of #41,250# people

  1. #42,075# people
  2. #42,917# people
  3. #43,775# people
  4. #44,651# people

Explanation:

#t_(0)=41,250# (the zero means your starting point)

Your rule for population increase in Springfield is
#t_a=t_(a-1)+0.02(t_(a-1))#

#a# means population you are about to calculate and #a-1# means the next year's population.

Therefore...

  • #a=0# with 41,250 people
  • #a=1# with 42,075 people
    #41,250+0.02(41,250)=41,250+825=42,075#
  • #a=2# with 42,917 people
    #42,075+0.02(42,075)=42,075+841.5=42,916.5\approx42,917#
    (#\color(indianred)(\text(You cannot have half a person, so round up.))#)
  • #a=3# with 43,775 people
    #42,917+0.02(42,917)=42,917+858.34=43,775.34\approx43,775#
    (#\color(indianred)(\text(You cannot have half a person, so round down.))#)
  • #a=4# with 44,651 people
    #43,775+0.02(43,775)=43,775+875.5=44,650.5\approx44,651#
    (#\color(indianred)(\text(You cannot have half a person, so round up.))#)