How do you solve #8^{3x}=154#?

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Answer 1 · 2018-07-03T20:31:43

#x={\log154}/{\log512}#

#8^{3x}=154#

#(2^3)^{3x}=154#

#2^{9x}=154#

#\log2^{9x}=\log154#

#9x\log2=\log154#

#x={\log154}/{9\log2}#

#x={\log154}/{\log2^9}#

#x={\log154}/{\log512}#