Question

How do you solve `-3log_(0.25)x<=6`?

Answer 1

`x<=16`

Explanation:

`-3log_0.25x<=6`
`-3log_(1/4)x<=6`
`3log_4x<=6` [Using the identity `log_(1/b)x=-log_bx`]
`log_4x<=2`
`x<=4^2`
`x<=16`