A point moves in #x-y# plane according to #vec r=3cos(4t)veci +3(1-sin4t) vecj#. What is the distance travelled by the particle in 0.5 sec ?
2 Answers
Explanation:
The position of particle at any time
Now, the position of particle at time
The position of particle at time
Now, the distance traveled by the particle in
Explanation:
Vector quantity position/displacement is:
Differentiate to obtain vector quantity velocity:
Scalar quantity speed
In any time period of