How do you solve #3y - 45= 3( 3y - 5)#?

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Answer 1 · 2018-07-06T00:06:41

#y=-5#

#3y-45=3(3y-5)#

#3y-45=9y-15#

#9y-3y=-45+15#

#6y=-30#

#y=-30/6#

#y=-5#

Answer 2 · 2018-07-06T00:10:06

#y=-5#

Let's factor a #3# out of the left side. Here, we are essentially dividing, and we get

#3(y-15)=3(3y-5)#

We can divide both sides by #3# to get

#y-15=3y-5#

Remember, we want all of our #y# terms on one side. We can further isolate #y# by adding #15# to both sides to get

#y=3y+10#

Subtracting #3y# from both sides gives us

#-2y=10#

Lastly, we can divide both sides by #-2# to get

#y=-5#

Hope this helps!