How do you rewrite 2 \times 372×37 as the sum of two products?

2 Answers
Jul 6, 2018

Set 37 as 100-63 giving: 2xx37->2xx(100-63)2×372×(10063)

[200]+[-126] [200]+[126]

Explanation:

2xx(37) = 742×(37)=74

'Split' the 37 (partition it) into the sum of any two numbers.

Just to be different I select such that one of them is negative.

Set 37=color(red)(100 - 63)37=10063 so we have:

color(green)(2xx(color(red)(37)) color(white)("d")-> color(white)("d")2xx(color(red)(100-63)) )2×(37)dd2×(10063)

Multiply everything inside the brackets by the 2 that is outside.

color(green)([2xxcolor(red)(100)] +[2xx(color(red)(-63))] )[2×100]+[2×(63)]

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color(blue)("Check")Check

[200]-[126] = 74 larr" As required"[200][126]=74 As required

Jul 6, 2018

color(brown)(=> 2 * 30 + 2 * 7230+27

Explanation:

2 * 37 = (2* (30 + 7))237=(2(30+7)) Distributive Law

=> 2 * 30 + 2 * 7230+27

We can write many such sum of two products.

=> 60 + 14 = 7460+14=74